3.687 \(\int (a+b \sin (e+f x))^3 (c+d \sin (e+f x))^2 \, dx\)

Optimal. Leaf size=315 \[ -\frac {\left (-6 a^3 d^2+60 a^2 b c d+a b^2 \left (100 c^2+71 d^2\right )+90 b^3 c d\right ) \sin (e+f x) \cos (e+f x)}{120 f}+\frac {1}{8} x \left (4 a^3 \left (2 c^2+d^2\right )+24 a^2 b c d+3 a b^2 \left (4 c^2+3 d^2\right )+6 b^3 c d\right )-\frac {\left (-3 a^4 d^2+30 a^3 b c d+4 a^2 b^2 \left (20 c^2+13 d^2\right )+120 a b^3 c d+4 b^4 \left (5 c^2+4 d^2\right )\right ) \cos (e+f x)}{30 b f}-\frac {\left (3 a d (10 b c-a d)+4 b^2 \left (5 c^2+4 d^2\right )\right ) \cos (e+f x) (a+b \sin (e+f x))^2}{60 b f}-\frac {d (10 b c-a d) \cos (e+f x) (a+b \sin (e+f x))^3}{20 b f}-\frac {d^2 \cos (e+f x) (a+b \sin (e+f x))^4}{5 b f} \]

[Out]

1/8*(24*a^2*b*c*d+6*b^3*c*d+4*a^3*(2*c^2+d^2)+3*a*b^2*(4*c^2+3*d^2))*x-1/30*(30*a^3*b*c*d+120*a*b^3*c*d-3*a^4*
d^2+4*b^4*(5*c^2+4*d^2)+4*a^2*b^2*(20*c^2+13*d^2))*cos(f*x+e)/b/f-1/120*(60*a^2*b*c*d+90*b^3*c*d-6*a^3*d^2+a*b
^2*(100*c^2+71*d^2))*cos(f*x+e)*sin(f*x+e)/f-1/60*(3*a*d*(-a*d+10*b*c)+4*b^2*(5*c^2+4*d^2))*cos(f*x+e)*(a+b*si
n(f*x+e))^2/b/f-1/20*d*(-a*d+10*b*c)*cos(f*x+e)*(a+b*sin(f*x+e))^3/b/f-1/5*d^2*cos(f*x+e)*(a+b*sin(f*x+e))^4/b
/f

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Rubi [A]  time = 0.46, antiderivative size = 315, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {2791, 2753, 2734} \[ -\frac {\left (4 a^2 b^2 \left (20 c^2+13 d^2\right )+30 a^3 b c d-3 a^4 d^2+120 a b^3 c d+4 b^4 \left (5 c^2+4 d^2\right )\right ) \cos (e+f x)}{30 b f}-\frac {\left (60 a^2 b c d-6 a^3 d^2+a b^2 \left (100 c^2+71 d^2\right )+90 b^3 c d\right ) \sin (e+f x) \cos (e+f x)}{120 f}+\frac {1}{8} x \left (24 a^2 b c d+4 a^3 \left (2 c^2+d^2\right )+3 a b^2 \left (4 c^2+3 d^2\right )+6 b^3 c d\right )-\frac {\left (3 a d (10 b c-a d)+4 b^2 \left (5 c^2+4 d^2\right )\right ) \cos (e+f x) (a+b \sin (e+f x))^2}{60 b f}-\frac {d (10 b c-a d) \cos (e+f x) (a+b \sin (e+f x))^3}{20 b f}-\frac {d^2 \cos (e+f x) (a+b \sin (e+f x))^4}{5 b f} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*Sin[e + f*x])^3*(c + d*Sin[e + f*x])^2,x]

[Out]

((24*a^2*b*c*d + 6*b^3*c*d + 4*a^3*(2*c^2 + d^2) + 3*a*b^2*(4*c^2 + 3*d^2))*x)/8 - ((30*a^3*b*c*d + 120*a*b^3*
c*d - 3*a^4*d^2 + 4*b^4*(5*c^2 + 4*d^2) + 4*a^2*b^2*(20*c^2 + 13*d^2))*Cos[e + f*x])/(30*b*f) - ((60*a^2*b*c*d
+ 90*b^3*c*d - 6*a^3*d^2 + a*b^2*(100*c^2 + 71*d^2))*Cos[e + f*x]*Sin[e + f*x])/(120*f) - ((3*a*d*(10*b*c - a
*d) + 4*b^2*(5*c^2 + 4*d^2))*Cos[e + f*x]*(a + b*Sin[e + f*x])^2)/(60*b*f) - (d*(10*b*c - a*d)*Cos[e + f*x]*(a
+ b*Sin[e + f*x])^3)/(20*b*f) - (d^2*Cos[e + f*x]*(a + b*Sin[e + f*x])^4)/(5*b*f)

Rule 2734

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[((2*a*c
+ b*d)*x)/2, x] + (-Simp[((b*c + a*d)*Cos[e + f*x])/f, x] - Simp[(b*d*Cos[e + f*x]*Sin[e + f*x])/(2*f), x]) /;
FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0]

Rule 2753

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> -Simp[(d
*Cos[e + f*x]*(a + b*Sin[e + f*x])^m)/(f*(m + 1)), x] + Dist[1/(m + 1), Int[(a + b*Sin[e + f*x])^(m - 1)*Simp[
b*d*m + a*c*(m + 1) + (a*d*m + b*c*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*
c - a*d, 0] && NeQ[a^2 - b^2, 0] && GtQ[m, 0] && IntegerQ[2*m]

Rule 2791

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^2, x_Symbol] :> -Simp[
(d^2*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m + 1))/(b*f*(m + 2)), x] + Dist[1/(b*(m + 2)), Int[(a + b*Sin[e + f*x
])^m*Simp[b*(d^2*(m + 1) + c^2*(m + 2)) - d*(a*d - 2*b*c*(m + 2))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c,
d, e, f, m}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] &&  !LtQ[m, -1]

Rubi steps

\begin {align*} \int (a+b \sin (e+f x))^3 (c+d \sin (e+f x))^2 \, dx &=-\frac {d^2 \cos (e+f x) (a+b \sin (e+f x))^4}{5 b f}+\frac {\int (a+b \sin (e+f x))^3 \left (b \left (5 c^2+4 d^2\right )+d (10 b c-a d) \sin (e+f x)\right ) \, dx}{5 b}\\ &=-\frac {d (10 b c-a d) \cos (e+f x) (a+b \sin (e+f x))^3}{20 b f}-\frac {d^2 \cos (e+f x) (a+b \sin (e+f x))^4}{5 b f}+\frac {\int (a+b \sin (e+f x))^2 \left (b \left (20 a c^2+30 b c d+13 a d^2\right )+\left (3 a d (10 b c-a d)+4 b^2 \left (5 c^2+4 d^2\right )\right ) \sin (e+f x)\right ) \, dx}{20 b}\\ &=-\frac {\left (3 a d (10 b c-a d)+4 b^2 \left (5 c^2+4 d^2\right )\right ) \cos (e+f x) (a+b \sin (e+f x))^2}{60 b f}-\frac {d (10 b c-a d) \cos (e+f x) (a+b \sin (e+f x))^3}{20 b f}-\frac {d^2 \cos (e+f x) (a+b \sin (e+f x))^4}{5 b f}+\frac {\int (a+b \sin (e+f x)) \left (b \left (150 a b c d+8 b^2 \left (5 c^2+4 d^2\right )+a^2 \left (60 c^2+33 d^2\right )\right )+\left (60 a^2 b c d+90 b^3 c d-6 a^3 d^2+a b^2 \left (100 c^2+71 d^2\right )\right ) \sin (e+f x)\right ) \, dx}{60 b}\\ &=\frac {1}{8} \left (24 a^2 b c d+6 b^3 c d+4 a^3 \left (2 c^2+d^2\right )+3 a b^2 \left (4 c^2+3 d^2\right )\right ) x-\frac {\left (30 a^3 b c d+120 a b^3 c d-3 a^4 d^2+4 b^4 \left (5 c^2+4 d^2\right )+4 a^2 b^2 \left (20 c^2+13 d^2\right )\right ) \cos (e+f x)}{30 b f}-\frac {\left (60 a^2 b c d+90 b^3 c d-6 a^3 d^2+a b^2 \left (100 c^2+71 d^2\right )\right ) \cos (e+f x) \sin (e+f x)}{120 f}-\frac {\left (3 a d (10 b c-a d)+4 b^2 \left (5 c^2+4 d^2\right )\right ) \cos (e+f x) (a+b \sin (e+f x))^2}{60 b f}-\frac {d (10 b c-a d) \cos (e+f x) (a+b \sin (e+f x))^3}{20 b f}-\frac {d^2 \cos (e+f x) (a+b \sin (e+f x))^4}{5 b f}\\ \end {align*}

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Mathematica [A]  time = 1.59, size = 246, normalized size = 0.78 \[ \frac {10 b \left (12 a^2 d^2+24 a b c d+b^2 \left (4 c^2+5 d^2\right )\right ) \cos (3 (e+f x))+15 \left (4 (e+f x) \left (4 a^3 \left (2 c^2+d^2\right )+24 a^2 b c d+3 a b^2 \left (4 c^2+3 d^2\right )+6 b^3 c d\right )-8 \left (a^3 d^2+6 a^2 b c d+3 a b^2 \left (c^2+d^2\right )+2 b^3 c d\right ) \sin (2 (e+f x))+b^2 d (3 a d+2 b c) \sin (4 (e+f x))\right )-60 \left (16 a^3 c d+6 a^2 b \left (4 c^2+3 d^2\right )+36 a b^2 c d+b^3 \left (6 c^2+5 d^2\right )\right ) \cos (e+f x)-6 b^3 d^2 \cos (5 (e+f x))}{480 f} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*Sin[e + f*x])^3*(c + d*Sin[e + f*x])^2,x]

[Out]

(-60*(16*a^3*c*d + 36*a*b^2*c*d + 6*a^2*b*(4*c^2 + 3*d^2) + b^3*(6*c^2 + 5*d^2))*Cos[e + f*x] + 10*b*(24*a*b*c
*d + 12*a^2*d^2 + b^2*(4*c^2 + 5*d^2))*Cos[3*(e + f*x)] - 6*b^3*d^2*Cos[5*(e + f*x)] + 15*(4*(24*a^2*b*c*d + 6
*b^3*c*d + 4*a^3*(2*c^2 + d^2) + 3*a*b^2*(4*c^2 + 3*d^2))*(e + f*x) - 8*(6*a^2*b*c*d + 2*b^3*c*d + a^3*d^2 + 3
*a*b^2*(c^2 + d^2))*Sin[2*(e + f*x)] + b^2*d*(2*b*c + 3*a*d)*Sin[4*(e + f*x)]))/(480*f)

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fricas [A]  time = 0.46, size = 253, normalized size = 0.80 \[ -\frac {24 \, b^{3} d^{2} \cos \left (f x + e\right )^{5} - 40 \, {\left (b^{3} c^{2} + 6 \, a b^{2} c d + {\left (3 \, a^{2} b + 2 \, b^{3}\right )} d^{2}\right )} \cos \left (f x + e\right )^{3} - 15 \, {\left (4 \, {\left (2 \, a^{3} + 3 \, a b^{2}\right )} c^{2} + 6 \, {\left (4 \, a^{2} b + b^{3}\right )} c d + {\left (4 \, a^{3} + 9 \, a b^{2}\right )} d^{2}\right )} f x + 120 \, {\left ({\left (3 \, a^{2} b + b^{3}\right )} c^{2} + 2 \, {\left (a^{3} + 3 \, a b^{2}\right )} c d + {\left (3 \, a^{2} b + b^{3}\right )} d^{2}\right )} \cos \left (f x + e\right ) - 15 \, {\left (2 \, {\left (2 \, b^{3} c d + 3 \, a b^{2} d^{2}\right )} \cos \left (f x + e\right )^{3} - {\left (12 \, a b^{2} c^{2} + 2 \, {\left (12 \, a^{2} b + 5 \, b^{3}\right )} c d + {\left (4 \, a^{3} + 15 \, a b^{2}\right )} d^{2}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{120 \, f} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sin(f*x+e))^3*(c+d*sin(f*x+e))^2,x, algorithm="fricas")

[Out]

-1/120*(24*b^3*d^2*cos(f*x + e)^5 - 40*(b^3*c^2 + 6*a*b^2*c*d + (3*a^2*b + 2*b^3)*d^2)*cos(f*x + e)^3 - 15*(4*
(2*a^3 + 3*a*b^2)*c^2 + 6*(4*a^2*b + b^3)*c*d + (4*a^3 + 9*a*b^2)*d^2)*f*x + 120*((3*a^2*b + b^3)*c^2 + 2*(a^3
+ 3*a*b^2)*c*d + (3*a^2*b + b^3)*d^2)*cos(f*x + e) - 15*(2*(2*b^3*c*d + 3*a*b^2*d^2)*cos(f*x + e)^3 - (12*a*b
^2*c^2 + 2*(12*a^2*b + 5*b^3)*c*d + (4*a^3 + 15*a*b^2)*d^2)*cos(f*x + e))*sin(f*x + e))/f

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giac [A]  time = 1.14, size = 274, normalized size = 0.87 \[ -\frac {b^{3} d^{2} \cos \left (5 \, f x + 5 \, e\right )}{80 \, f} + \frac {1}{8} \, {\left (8 \, a^{3} c^{2} + 12 \, a b^{2} c^{2} + 24 \, a^{2} b c d + 6 \, b^{3} c d + 4 \, a^{3} d^{2} + 9 \, a b^{2} d^{2}\right )} x + \frac {{\left (4 \, b^{3} c^{2} + 24 \, a b^{2} c d + 12 \, a^{2} b d^{2} + 5 \, b^{3} d^{2}\right )} \cos \left (3 \, f x + 3 \, e\right )}{48 \, f} - \frac {{\left (24 \, a^{2} b c^{2} + 6 \, b^{3} c^{2} + 16 \, a^{3} c d + 36 \, a b^{2} c d + 18 \, a^{2} b d^{2} + 5 \, b^{3} d^{2}\right )} \cos \left (f x + e\right )}{8 \, f} + \frac {{\left (2 \, b^{3} c d + 3 \, a b^{2} d^{2}\right )} \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} - \frac {{\left (3 \, a b^{2} c^{2} + 6 \, a^{2} b c d + 2 \, b^{3} c d + a^{3} d^{2} + 3 \, a b^{2} d^{2}\right )} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sin(f*x+e))^3*(c+d*sin(f*x+e))^2,x, algorithm="giac")

[Out]

-1/80*b^3*d^2*cos(5*f*x + 5*e)/f + 1/8*(8*a^3*c^2 + 12*a*b^2*c^2 + 24*a^2*b*c*d + 6*b^3*c*d + 4*a^3*d^2 + 9*a*
b^2*d^2)*x + 1/48*(4*b^3*c^2 + 24*a*b^2*c*d + 12*a^2*b*d^2 + 5*b^3*d^2)*cos(3*f*x + 3*e)/f - 1/8*(24*a^2*b*c^2
+ 6*b^3*c^2 + 16*a^3*c*d + 36*a*b^2*c*d + 18*a^2*b*d^2 + 5*b^3*d^2)*cos(f*x + e)/f + 1/32*(2*b^3*c*d + 3*a*b^
2*d^2)*sin(4*f*x + 4*e)/f - 1/4*(3*a*b^2*c^2 + 6*a^2*b*c*d + 2*b^3*c*d + a^3*d^2 + 3*a*b^2*d^2)*sin(2*f*x + 2*
e)/f

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maple [A]  time = 0.32, size = 325, normalized size = 1.03 \[ \frac {a^{3} c^{2} \left (f x +e \right )-2 a^{3} c d \cos \left (f x +e \right )+a^{3} d^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-3 a^{2} b \,c^{2} \cos \left (f x +e \right )+6 a^{2} b c d \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-a^{2} b \,d^{2} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )+3 a \,b^{2} c^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-2 a \,b^{2} c d \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )+3 a \,b^{2} d^{2} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {b^{3} c^{2} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+2 b^{3} c d \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {b^{3} d^{2} \left (\frac {8}{3}+\sin ^{4}\left (f x +e \right )+\frac {4 \left (\sin ^{2}\left (f x +e \right )\right )}{3}\right ) \cos \left (f x +e \right )}{5}}{f} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*sin(f*x+e))^3*(c+d*sin(f*x+e))^2,x)

[Out]

1/f*(a^3*c^2*(f*x+e)-2*a^3*c*d*cos(f*x+e)+a^3*d^2*(-1/2*sin(f*x+e)*cos(f*x+e)+1/2*f*x+1/2*e)-3*a^2*b*c^2*cos(f
*x+e)+6*a^2*b*c*d*(-1/2*sin(f*x+e)*cos(f*x+e)+1/2*f*x+1/2*e)-a^2*b*d^2*(2+sin(f*x+e)^2)*cos(f*x+e)+3*a*b^2*c^2
*(-1/2*sin(f*x+e)*cos(f*x+e)+1/2*f*x+1/2*e)-2*a*b^2*c*d*(2+sin(f*x+e)^2)*cos(f*x+e)+3*a*b^2*d^2*(-1/4*(sin(f*x
+e)^3+3/2*sin(f*x+e))*cos(f*x+e)+3/8*f*x+3/8*e)-1/3*b^3*c^2*(2+sin(f*x+e)^2)*cos(f*x+e)+2*b^3*c*d*(-1/4*(sin(f
*x+e)^3+3/2*sin(f*x+e))*cos(f*x+e)+3/8*f*x+3/8*e)-1/5*b^3*d^2*(8/3+sin(f*x+e)^4+4/3*sin(f*x+e)^2)*cos(f*x+e))

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maxima [A]  time = 0.52, size = 314, normalized size = 1.00 \[ \frac {480 \, {\left (f x + e\right )} a^{3} c^{2} + 360 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a b^{2} c^{2} + 160 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} b^{3} c^{2} + 720 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} b c d + 960 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a b^{2} c d + 30 \, {\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} b^{3} c d + 120 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{3} d^{2} + 480 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a^{2} b d^{2} + 45 \, {\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} a b^{2} d^{2} - 32 \, {\left (3 \, \cos \left (f x + e\right )^{5} - 10 \, \cos \left (f x + e\right )^{3} + 15 \, \cos \left (f x + e\right )\right )} b^{3} d^{2} - 1440 \, a^{2} b c^{2} \cos \left (f x + e\right ) - 960 \, a^{3} c d \cos \left (f x + e\right )}{480 \, f} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sin(f*x+e))^3*(c+d*sin(f*x+e))^2,x, algorithm="maxima")

[Out]

1/480*(480*(f*x + e)*a^3*c^2 + 360*(2*f*x + 2*e - sin(2*f*x + 2*e))*a*b^2*c^2 + 160*(cos(f*x + e)^3 - 3*cos(f*
x + e))*b^3*c^2 + 720*(2*f*x + 2*e - sin(2*f*x + 2*e))*a^2*b*c*d + 960*(cos(f*x + e)^3 - 3*cos(f*x + e))*a*b^2
*c*d + 30*(12*f*x + 12*e + sin(4*f*x + 4*e) - 8*sin(2*f*x + 2*e))*b^3*c*d + 120*(2*f*x + 2*e - sin(2*f*x + 2*e
))*a^3*d^2 + 480*(cos(f*x + e)^3 - 3*cos(f*x + e))*a^2*b*d^2 + 45*(12*f*x + 12*e + sin(4*f*x + 4*e) - 8*sin(2*
f*x + 2*e))*a*b^2*d^2 - 32*(3*cos(f*x + e)^5 - 10*cos(f*x + e)^3 + 15*cos(f*x + e))*b^3*d^2 - 1440*a^2*b*c^2*c
os(f*x + e) - 960*a^3*c*d*cos(f*x + e))/f

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mupad [B]  time = 8.52, size = 358, normalized size = 1.14 \[ -\frac {90\,b^3\,c^2\,\cos \left (e+f\,x\right )+75\,b^3\,d^2\,\cos \left (e+f\,x\right )-10\,b^3\,c^2\,\cos \left (3\,e+3\,f\,x\right )-\frac {25\,b^3\,d^2\,\cos \left (3\,e+3\,f\,x\right )}{2}+\frac {3\,b^3\,d^2\,\cos \left (5\,e+5\,f\,x\right )}{2}+30\,a^3\,d^2\,\sin \left (2\,e+2\,f\,x\right )-30\,a^2\,b\,d^2\,\cos \left (3\,e+3\,f\,x\right )+90\,a\,b^2\,c^2\,\sin \left (2\,e+2\,f\,x\right )+90\,a\,b^2\,d^2\,\sin \left (2\,e+2\,f\,x\right )-\frac {45\,a\,b^2\,d^2\,\sin \left (4\,e+4\,f\,x\right )}{4}+240\,a^3\,c\,d\,\cos \left (e+f\,x\right )+360\,a^2\,b\,c^2\,\cos \left (e+f\,x\right )+270\,a^2\,b\,d^2\,\cos \left (e+f\,x\right )+60\,b^3\,c\,d\,\sin \left (2\,e+2\,f\,x\right )-\frac {15\,b^3\,c\,d\,\sin \left (4\,e+4\,f\,x\right )}{2}-120\,a^3\,c^2\,f\,x-60\,a^3\,d^2\,f\,x-60\,a\,b^2\,c\,d\,\cos \left (3\,e+3\,f\,x\right )+180\,a^2\,b\,c\,d\,\sin \left (2\,e+2\,f\,x\right )-180\,a\,b^2\,c^2\,f\,x-135\,a\,b^2\,d^2\,f\,x+540\,a\,b^2\,c\,d\,\cos \left (e+f\,x\right )-90\,b^3\,c\,d\,f\,x-360\,a^2\,b\,c\,d\,f\,x}{120\,f} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*sin(e + f*x))^3*(c + d*sin(e + f*x))^2,x)

[Out]

-(90*b^3*c^2*cos(e + f*x) + 75*b^3*d^2*cos(e + f*x) - 10*b^3*c^2*cos(3*e + 3*f*x) - (25*b^3*d^2*cos(3*e + 3*f*
x))/2 + (3*b^3*d^2*cos(5*e + 5*f*x))/2 + 30*a^3*d^2*sin(2*e + 2*f*x) - 30*a^2*b*d^2*cos(3*e + 3*f*x) + 90*a*b^
2*c^2*sin(2*e + 2*f*x) + 90*a*b^2*d^2*sin(2*e + 2*f*x) - (45*a*b^2*d^2*sin(4*e + 4*f*x))/4 + 240*a^3*c*d*cos(e
+ f*x) + 360*a^2*b*c^2*cos(e + f*x) + 270*a^2*b*d^2*cos(e + f*x) + 60*b^3*c*d*sin(2*e + 2*f*x) - (15*b^3*c*d*
sin(4*e + 4*f*x))/2 - 120*a^3*c^2*f*x - 60*a^3*d^2*f*x - 60*a*b^2*c*d*cos(3*e + 3*f*x) + 180*a^2*b*c*d*sin(2*e
+ 2*f*x) - 180*a*b^2*c^2*f*x - 135*a*b^2*d^2*f*x + 540*a*b^2*c*d*cos(e + f*x) - 90*b^3*c*d*f*x - 360*a^2*b*c*
d*f*x)/(120*f)

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sympy [A]  time = 4.29, size = 729, normalized size = 2.31 \[ \begin {cases} a^{3} c^{2} x - \frac {2 a^{3} c d \cos {\left (e + f x \right )}}{f} + \frac {a^{3} d^{2} x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {a^{3} d^{2} x \cos ^{2}{\left (e + f x \right )}}{2} - \frac {a^{3} d^{2} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} - \frac {3 a^{2} b c^{2} \cos {\left (e + f x \right )}}{f} + 3 a^{2} b c d x \sin ^{2}{\left (e + f x \right )} + 3 a^{2} b c d x \cos ^{2}{\left (e + f x \right )} - \frac {3 a^{2} b c d \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {3 a^{2} b d^{2} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {2 a^{2} b d^{2} \cos ^{3}{\left (e + f x \right )}}{f} + \frac {3 a b^{2} c^{2} x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {3 a b^{2} c^{2} x \cos ^{2}{\left (e + f x \right )}}{2} - \frac {3 a b^{2} c^{2} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} - \frac {6 a b^{2} c d \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {4 a b^{2} c d \cos ^{3}{\left (e + f x \right )}}{f} + \frac {9 a b^{2} d^{2} x \sin ^{4}{\left (e + f x \right )}}{8} + \frac {9 a b^{2} d^{2} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} + \frac {9 a b^{2} d^{2} x \cos ^{4}{\left (e + f x \right )}}{8} - \frac {15 a b^{2} d^{2} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{8 f} - \frac {9 a b^{2} d^{2} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} - \frac {b^{3} c^{2} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {2 b^{3} c^{2} \cos ^{3}{\left (e + f x \right )}}{3 f} + \frac {3 b^{3} c d x \sin ^{4}{\left (e + f x \right )}}{4} + \frac {3 b^{3} c d x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{2} + \frac {3 b^{3} c d x \cos ^{4}{\left (e + f x \right )}}{4} - \frac {5 b^{3} c d \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{4 f} - \frac {3 b^{3} c d \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{4 f} - \frac {b^{3} d^{2} \sin ^{4}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {4 b^{3} d^{2} \sin ^{2}{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{3 f} - \frac {8 b^{3} d^{2} \cos ^{5}{\left (e + f x \right )}}{15 f} & \text {for}\: f \neq 0 \\x \left (a + b \sin {\relax (e )}\right )^{3} \left (c + d \sin {\relax (e )}\right )^{2} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sin(f*x+e))**3*(c+d*sin(f*x+e))**2,x)

[Out]

Piecewise((a**3*c**2*x - 2*a**3*c*d*cos(e + f*x)/f + a**3*d**2*x*sin(e + f*x)**2/2 + a**3*d**2*x*cos(e + f*x)*
*2/2 - a**3*d**2*sin(e + f*x)*cos(e + f*x)/(2*f) - 3*a**2*b*c**2*cos(e + f*x)/f + 3*a**2*b*c*d*x*sin(e + f*x)*
*2 + 3*a**2*b*c*d*x*cos(e + f*x)**2 - 3*a**2*b*c*d*sin(e + f*x)*cos(e + f*x)/f - 3*a**2*b*d**2*sin(e + f*x)**2
*cos(e + f*x)/f - 2*a**2*b*d**2*cos(e + f*x)**3/f + 3*a*b**2*c**2*x*sin(e + f*x)**2/2 + 3*a*b**2*c**2*x*cos(e
+ f*x)**2/2 - 3*a*b**2*c**2*sin(e + f*x)*cos(e + f*x)/(2*f) - 6*a*b**2*c*d*sin(e + f*x)**2*cos(e + f*x)/f - 4*
a*b**2*c*d*cos(e + f*x)**3/f + 9*a*b**2*d**2*x*sin(e + f*x)**4/8 + 9*a*b**2*d**2*x*sin(e + f*x)**2*cos(e + f*x
)**2/4 + 9*a*b**2*d**2*x*cos(e + f*x)**4/8 - 15*a*b**2*d**2*sin(e + f*x)**3*cos(e + f*x)/(8*f) - 9*a*b**2*d**2
*sin(e + f*x)*cos(e + f*x)**3/(8*f) - b**3*c**2*sin(e + f*x)**2*cos(e + f*x)/f - 2*b**3*c**2*cos(e + f*x)**3/(
3*f) + 3*b**3*c*d*x*sin(e + f*x)**4/4 + 3*b**3*c*d*x*sin(e + f*x)**2*cos(e + f*x)**2/2 + 3*b**3*c*d*x*cos(e +
f*x)**4/4 - 5*b**3*c*d*sin(e + f*x)**3*cos(e + f*x)/(4*f) - 3*b**3*c*d*sin(e + f*x)*cos(e + f*x)**3/(4*f) - b*
*3*d**2*sin(e + f*x)**4*cos(e + f*x)/f - 4*b**3*d**2*sin(e + f*x)**2*cos(e + f*x)**3/(3*f) - 8*b**3*d**2*cos(e
+ f*x)**5/(15*f), Ne(f, 0)), (x*(a + b*sin(e))**3*(c + d*sin(e))**2, True))

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